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The decay constant , for a given radioactive sample, is 0.3465 "day"^(-1) .What percentage of this sample will get decayed in a period of 4 days ? |
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Answer» `100%` `T_(1//2)=0.693/lambda=0.693/0.3465`=2 days `therefore n=1/T_(1//2)=4/2`=2 HENCE, sample LEFT decayed after a period of 4 days. `N/N_0=(1/2)^2 =(1/4)`=25% `therefore ` Sample decayed = 75% |
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