The decay constant of a radioactive isotope is lambda. If A_1 and A_2 are its activites at time t_1 and t_2 respectively, then the number of nuclei which have decayed the time (t_1-t_2)

The decay constant of a radioactive isotope is lambda. If A_1 and A_2

1.	The decay constant of a radioactive isotope is lambda. If A_1 and A_2 are its activites at time t_1 and t_2 respectively, then the number of nuclei which have decayed the time (t_1-t_2)
Answer» `A_1t_1-A_2t_2` `A_1-A_2` `(A_1-A_2)//LAMBDA` `lambda(A_1-A_2)` Solution :`A_1=lambdaN_1` at time `t_1` `A_2=lambdaN_2` at time `t_2` Therefore, number of NUCLEI DECAYED during time INTERVAL `(t_1-t_2)` is `N_1-N_2=((A_1-A_2))/lambda`

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The decay constant of a radioactive isotope is lambda. If A_1 and A_2 are its activites at time t_1 and t_2 respectively, then the number of nuclei which have decayed the time (t_1-t_2)

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