1.

The decay constant of a radioactive sample is 'lamda'. The half-life and mean life of the sample are respectively

Answer»

`(1)/(lamda), (LN 2)/(lamda)`
`(ln 2)/(lamda), (1)/(lamda)`
`lamda ln 2, (1)/(lamda)`
`(lamda)/(ln 2), (1)/(lamda)`

Solution :`t_(1//2) = (log_(E)2)/(lamda)`, Average life `= (1)/(lamda)`


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