1.

The decomposition of a hydrocarbon follows the equation k = (45 x 1011s-1)e-28000 k/T Calculate activation energy (Ea).

Answer»

According to Arrhenius equation,
k= Ae-Ea/RT                 …. (1)
According to equation
k= (4.5 x 1011 s-1)e-28000 k/T           …..(2)
Compare equation (1) and (2)
\(-\frac { Ea }{ RT } =\frac { -28000K }{ T }\)
or      Ea = 28000 K x R
or      Ea = 28000 K x 8.314J K-1mol-1
Ea = 232792 J/mol
Ea = 232.79 kJ/mol
The activation energy is 232.79 kJ/mol



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