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The decomposition of A into products has value of k as 4.5xx10^(3)s^(-1) at 10""^(@)C and energy of activation 60" kJ mol"^(-1). At what ttemperature would k be 1.5xx10^(4)s^(-1) ? |
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Answer» Solution :`k_(1)=4.5xx10^(3)s^(-1),T_(1)=10+273" K"=283" K",k_(2)=1.5xx10^(4)s^(-1),T_(2)=?,E_(a)=60" kJ mol"^(-1)` APPLYING Arrhenius equation, `log""(k_(2))/(k_(1))=(E_(a))/(2.303" R")((T_(2)-T_(1))/(T_(1)T_(2)))` `log""(1.5xx10^(4))/(4.5xx10^(3))=(60000" J mol"^(-1))/(2.303xx8.314" JK"^(-1)" mol"^(1))((T_(2)-283)/(283T_(2)))` or `log3.333=3133.63((T_(2)-283)/(283t_(2)))" or "(0.5228)/(3133.63)=(T_(2)-283)/(283T_(2))" or "0.0472T_(2)=T_(2)-283` or `0.9528T_(2)=283" or "T_(2)=(283)/(0.9528)=297" K"=297-273""^(@)C=24""^(@)C.` |
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