1.

The decomposition of hydrocarbon follows the equation k=(4.5xx10^(11)s^(-1))e^(-28000K//T) Calculate E_(a)

Answer»

Solution :K=`4.5xx10^(11)s^(-1)e^(-28000 K//T)`
Calculation of `E_(a)`,here ,k indicate TEMPERATURE in kelvin.
According to Arrhenius k=`Ae^(-E_(a)//RT)` …….(b)
`therefore` Compairing (a) and (b)so,In (a)`4.5xx10^(11)` is K of (b).
In (a),`e^(-28000K//T)`=In (b),`e^(-E_(a)//RT)`
means,`-(E_(a))/(RT)=-(28000K)/(T)`
`therefore E_(a)=28000 KxxR`


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