1.

The decomposition of hydrocarbon follows the equation K = (1.5 × 1011 s-1) \(e \frac{-28000K}{T}\). Calculate Ea

Answer»

According to Arrhenius equation K = Ae-Ea/RT 

Given K = (4.5 × 1011s-1)\(e \frac{-28000K}{T}\)

comparing the two equations

\(\frac{E_a}{RT} = \frac{-28000K}{T}\)

Ea = 28000 × R 

= 28000 × 8.314 J mol-1 

= 232.79 KJ mol-1



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