InterviewSolution
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InterviewSolution
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The decomposition of `N_(2)O_(4)` to `NO_(2)` is carried out at `280^(@)C` in chloroform. When equilibrium is reached, `0.2` mol of `N_(2)O_(4)` and `2xx10^(-3)` mol of `NO_(2)` are present in a `2L` solution. The equilibrium constant for the reaction `N_(2)O_(4) hArr 2NO_(2)` isA. `1xx10^(-2)`B. `2xx10^(-3)`C. `1xx10^(-5)`D. `2xx10^(-5)` |
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Answer» Correct Answer - C `{:(,N_(2)O_(4),hArr,2NO_(2)),("Initial",1,,0),("Final",1-x,,2x),(,1-x=0.2 "mol",,2x=2xx10^(-3) "mol"):}` `[N_(2)O_(4)]=0.2/2=0.1 M [NO_(2)]=(2xx10^(-3))/(2)=10^(-3) M` `K=([NO_(2)]^(2))/([N_(2)O_(4)])=((10^(-3))^(2))/0.1=10^(-5)` |
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