1.

The decomposition of N_2O_4 to NO_2 is carried out at 280 K in chloroform.When equiliberium has been established,0.2 mole of N_2O_4 and 2 xx 10^(-3) mole of NO_2 are present in a 2 litre solution. THE equiliberium constant for the reaction, N_2O_4 ⇌ 2NO_2 is :

Answer»

`1 xx 10^(-2)`
`1 xx 10^(-3)`
`1 xx 10^(-5)`
`2 xx 10^(-5)`

Answer :C


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