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The decomposition of phosphine (PH_(3)) on tungsten at low pressure is a first order reaction. It is because the |
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Answer» SOLUTION :`(t_(1))/(t_(2))=((a_(2))/(a_(1)))^(n-1)` `a_(1)="290 MM of Hg "t_(1)="263 seconds"` `a_(2)="360 mm of Hg "t_(2)="212 seconds"` `(263)/(212)=((360)/(290))^(n-1)` `1.24=(1.24)^(n-1)` `n-1=1` `n=1+1=2` Hence, the REACTION is of second order. |
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