1.

The decreasing order of aromaticity fo the following is I. Benzene, II. Napthalene, III. Anthrance

Answer»

`(I) gt (II) gt (III)`
(IIII) gt (II) gt (I)`
`(II) gt (I) gt (III)`
`(II) gt (IIII) gt (I)`

Solution :`R.E`. Of benzene napathalene and anthrancene, respectively are `151,255`, and `351 KJ MOL^(-1)`
`E.E.//` ring of napthalene (two rings) `= 255//2`
`= 127.5 kJ mol^(-1)`
`R.E.//"ring"` of anthrance (THREE rings) `= 351//3`
`= 117 kJ mol^(-1)`
On the basic of `R.E.//"ring", R.E`. of `"benzene"gt"of napathalene" gt "of anthrance".


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