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The denominator of a rational number is greater than its numerator by 7 if numerator is increased by 19 and denominator is decreased by 3 the new number become 4 find the original numberplz tell me fast​

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Answer:-

The Original Rational Number Is \bf\dfrac{1}{8}.

Explanation:-

Given:-

  • The Denominator of a rational Number is greater than its numerator by 7.

  • If the numerator is increased by 19 and denominator is decreased by 4 the result would be equal to 4.

To FIND:-

  • The original number.

So,

Let the numerator of the rational number be x.

So its denominator will be equal to x + 7.

And The Original Number will be, \bf\dfrac{x}{x+7}.

THEREFORE Acc. To Que.:-

\tt\mapsto4 =  \dfrac{x+ 19}{x + 7 - 3}  . \\

\tt\mapsto4 =  \dfrac{x + 19}{x + 4}. \\

\tt\mapsto4(x + 4) = x + 19. \\

\tt\mapsto4x + 16 =x + 19. \\

\tt\mapsto4x - x = 19 - 16. \\

\tt\mapsto3x = 3. \\

\tt\mapsto x =  \cancel \dfrac{3}{3} . \\

\large \red{\mapsto \boxed{ \blue{ \bf x = 1.}}}

Therefore The Original Number is,

\tt=  \dfrac{x}{x + 7} . \\

\tt =  \dfrac{1}{1 + 7} . \\

\large\red{\boxed{\blue{ \bf  =  \frac{1}{8}.}}}

So The Required Rational Number is 1/8.



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