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THE DENOMINATOR OF A RATIONAL NUMBER IS GREATER THAN THE NUMERATOR BY 5. IF THE NUMERATOR IS INCREASED BY 11 AND THE DENOMINATOR IS DECREASED BY 3 . THE RESULT OBTAINED IS 5/2 FIND THE RATIONAL NUMBER |
Answer» Answer:- let NUMERATOR be = Xdenominator = x + 5numerator increased by 11 = 11 + xdenominator decreased by 3 = x + 5 - 3= 2= x + 11 + 5/2x + 2now cross MULTIPLY= 2 (x+11) = 3(x+2)use the distributive property = 2x+22 = 3x+6now group the numbers and change the signs while grouping = 2x-3x = 6-22= -x = -16cancel the signs as it is common = x = 16therefore N= 16D= 16+5=21ANSWER=16/21HOPE IT HELPS YOUHAVE A GREAT DAY.... |
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