1.

The density (in g mL^(-1)) of a 3.60M sulphuric acid solution that is 29% H_(2)SO_(4) (Molar mass = 98 g mol^(-1)) by mass will be

Answer»

1.45
1.64
1.88
1.22

Solution :By DEFINITION, `3.6 M (3xx98=352.8 g) of H_(2)SO_(4)` are present in 1000 mL of solution.
29.0 g of acid are present in solution=100 g
325.8 of acid are present in soluion
`((100g))/((29.0 g))xx(352.8 g)`
=1216 g
`"Density of solution"=("Mass of solution")/("Volume of solution")`
`((1216g))/((1000ML))=`1.22 g `mol^(-1)`


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