InterviewSolution
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InterviewSolution
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The density of `3 M` sodium of thiosulphate solution `(Na_(2)S_(2)O_(3))` is `1.25 g mL^(-1)`. Calculate a. The precentage by weight of sodium thiosulphate. b. The mole fraction of sodium thiosulphate. c. The molalities of `Na^(o+)` and `S_(2)O_(3)^(2-)` ions.A. `12.65%`B. `37.92%`C. `0.87%`D. `63.21%` |
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Answer» Correct Answer - B `"Molecular weight of "Na_(2)S_(2)O_(3)=158g" mol"^(-1)` From, molarity `=(%"by weight of solute" xx"density of solution"xx10)/(M)` `3=(%"by weight of"Na_(2)S_(2)O_(3)xx1.25xx10)/(158)` `:.%"by weight of "Na_(2)S_(2)O_(2)=(3xx158)/(1.25xx10)=37.92%` |
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