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The density of a liquid of coefficient of cubical expansion gamma is d at 0^(@)C. When the liquid is heated to a temperature T, the change in density will be : |
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Answer» `(-gamma T d_(0))/((1+gamma T))` `d_(t) =(d_(0))/(1+gamma T)` `therefore` Change is density `=d_(e)-d_(0)=(d_(0))/(1+gamma T)-d_(0)` `=(d_(0)-d_(0)-gamma Td_(0))/(1+gamma T)=(-gamma Td_(0))/(1+gamma T)` Thus, correct choice is (a). |
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