1.

The density of a rod of 1 m and of non-uniform structure is given by rho(x)=a(1+bx^(2)), where a and b are constant such that alexle1. The centre of mass of the rod will be at :

Answer»

`(3[2+b])/(4[3+b])`
`(4[2+b])/(3[3+b])`
`(3[3+b])/(4[2+b])`
`(4[3+b])/(3[2+b])`

SOLUTION :Here `RHO(x)=1+bx^(2)`. Now `rho` will be CONSTANT when `b=0`, otherwise it will be dependent on .x.. The CENTRE of mass is at `x=0.5` m for uniform density of the rod.


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