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The density of a solid at normal pressure is p. When the solid is subjected to an excess pressure P_(1), the density changes top'. If the bulk modulus of the solid is k, then the ratio (p')/p is |
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Answer» `1+p/k` `thereforedp=(-m)/(V^(2))DV` `therefore(dp)/P=(-dV)/V` Substituting this VALUE in bulk MODULUS, K`=(-P)/(dV//V)` `K=(-P)/((-dp)/p)=(PP)/(dp)` with increase in pressure, the density increases `thereforedp=p.-p` `thereforeK=(Pp)/(p.-p)` `therefore(p.-p)/p=p/K` `(p.)/p=(1+p)/K` so correct choice is (a). |
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