1.

The density of an electron - hole pair in a pure germanium is 3xx10^(-16) m^(-3)at room temperature. On doping with aluminium , the hole density increase to 4.5xx10^(22) m^(-3)Now the electron density ( in m )in doped germanium will be

Answer»

`1XX10^(10)`
`2xx10^(10)`
`0.5xx10^(10)`
`4xx10^(10)`

SOLUTION :`n_(i)^(2)=n_(h)n_(e)rArrn_(e)=((3xx10^(16))^(2))/(4.5xx10^(22))=(9XX10^(12))/(4.5xx10^(22))=2xx10^(10)m^(-3)`


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