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The density of gas `A` is twice that of B at the same temperature the molecular weight of gas B is twice that of A. The ratio of pressure of gas A and B will be :A. `1:6`B. `1:1`C. `4:1`D. `1:4` |
Answer» Correct Answer - c (c) `d_(A)=2d_(B)," "3M_(A)=M_(B)," " PM=dRT` `=(P_(A))/(P_(B))xx(M_(A))/(M_(B))xx(d_(A))/(d_(B))xx(RT)/(RT)` `=(P_(A))/(P_(B))xx(1)/(2)=2` `(P_(A))/(P_(B))=(4)/(1)` |
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