

InterviewSolution
Saved Bookmarks
1. |
The density of oxygen at N.T.P. is `16xx0.089kg//m^(3)` then the R.M.S. velocity of oxygen molecules at N.T.P. would beA. `4.6xx10^(2)m//s`B. `46xx10^(2)m//s`C. `0.46xx10^(2)m//s`D. `3.6xx10^(2)m//s` |
Answer» Correct Answer - A `C=sqrt((3P)/(rho))=sqrt((3xx10^(5))/(16xx90xx10^(-3)))` `C=sqrt((3xx10^(7))/(16xx93))=sqrt((10xx10^6)/(16xx3))=sqrt((3.33)/(16)xx10^(6))` `=(1.8xx10^(3))/(4)=0.45xx10^(3)=450m//s`. |
|