InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The density of the core a planet is `rho_(1)` and that of the outer shell is `rho_(2)`. The radii of the core and that of the planet are `R` and `2R` respectively. The acceleration due to gravity at the surface of the planet is same as at a depth `R`. Find the ratio of `(rho_(1))/(rho_(2))` A. `3//4`B. `5//3`C. `7//3`D. `3//5` |
|
Answer» Correct Answer - C Let `m_(1)` is mass of core and `m_(2)` outer portion `m_(1)=4/3piR^(3) rho_(1), m_(2)=4/3pi[(2R)^(3)-R^(3)] rho_(2)` Given that `(Gm_(1))/(R^(2))=(G(m_(1)+m_(2)))/((2R)^(2)) implies (rho_(1))/(rho_(2))=7/3` |
|