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The density of the core of planet is `rho_(1)` and that of the outer shell is `rho_(2)`. The radius of the core that of the planet are R and 2R respectively. Gravitastional intensity at the surface of the planet is same as at a depth R. Find the ratio `(rho_(1))/(rho_(2))` , assuming them to be uniform independently. |
Answer» Correct Answer - `7//3` `(GM_("core"))/(R^(2))=(GM_("Total"))/(4R^(2)), (G(4)/(3)piR^(3)rho)/(R^(2))=(G(4)/(3)piR^(3)[rho_(1)+7rho_(2)])/(4R^(2))` `4rho_(1)=rho_(1)+7rho_(2) rArr (rho_(1))/(rho_(2))=(7)/(3)` |
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