The density of vapour of a substance `(X)` at 1 atm pressure and 500 K is `0.8 kg//m^(3)`. The vapour effuse through a small hole at a rate of `4//5` times slower than oxygen under the same condition. What is the compressibility factor `(z)` of the vapour ?A. `0.974`B. `1.35`C. `1.52`D. `1.22`

The density of vapour of a substance `(X)` at 1 atm pressure and 500 K

1.	The density of vapour of a substance `(X)` at 1 atm pressure and 500 K is `0.8 kg//m^(3)`. The vapour effuse through a small hole at a rate of `4//5` times slower than oxygen under the same condition. What is the compressibility factor `(z)` of the vapour ?A. `0.974`B. `1.35`C. `1.52`D. `1.22`
Answer» Correct Answer - C `(r_(X))/(r_(O_(2)))=sqrt((MO_(2))/(M_(x)))=((4)/(5))^(2)=(32)/(M_(x))` `M_(x)=50` `d_(x)=0.80kg//m^(3)` `V_(m)=(1000)/(800)xx50=62.5L` `Z=(PV_(m))/(RT)=(1xx62.5)/(0.0821xx500)=1.52`

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The density of vapour of a substance `(X)` at 1 atm pressure and 500 K is `0.8 kg//m^(3)`. The vapour effuse through a small hole at a rate of `4//5` times slower than oxygen under the same condition. What is the compressibility factor `(z)` of the vapour ?A. `0.974`B. `1.35`C. `1.52`D. `1.22`

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