InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The depth `d`, at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)A. `(R)/(n)`B. `R((n-1)/(n))`C. `(R)/(n^(2))`D. `R((n)/(n+1))` |
|
Answer» Correct Answer - b `g_(d)=g(1+(d)/(R))` `(1)/(n)g=g(1-(d)/(R))` `(1)/(n)-1=-(d)/(R)` `(1)/(n)-1=-(d)/(R)` `-1(1)/(n)=(d)/(R)` `((n-1)/(n))R=d` `therefore" "d=((n-1)/(n))R.` |
|