InterviewSolution
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InterviewSolution
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The depth `d`, at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)A. `(R )/(n)`B. `R(n-1)/(n)`C. `(R )/(n^(2))`D. `R(n)/(n+1)` |
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Answer» Correct Answer - B At depth `g =g(1-(h)/(R )) or (1-(d)/(R ))` `(g)/(g)=(1)/(n)=(1-(d)/(R ))=(1)/(n)=(1-(d)/(R )) rarr d=R(n-1)/(n)` |
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