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The derivative of log (sin(logx) (x > 0) |
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Answer» ( cos ( ㏒ x ) ) / ( x . sin ( ㏒ x ) )Step-by-step explanation:LET : y = ㏒ ( sin ( ㏒ x ) ) , x > 0 # ㏒ x = ㏒_e x = ㏑ XWE KNOW : = > ( ㏑ x )' = 1 / x= > y' = 1 / sin ( ㏒ x ) . ( sin ( ㏒ x ) )'= > y' = 1 / sin ( ㏒ x ) . ( cos ( ㏒ x ) ) . ( ㏒ x )'= > y' = 1 / sin ( ㏒ x ) . ( cos ( ㏒ x ) ) . 1 / x= > y' = ( cos ( ㏒ x ) ) / ( x . sin ( ㏒ x ) )Hence we GET required answer! |
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