The design capacity of channel/I-section purlin is given by(a) M = Zp/fy(b) M = Zpγm0fy(c) M = Zpγm0/fy(d) M = γm0/fyI have been asked this question in unit test.This question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

The design capacity of channel/I-section purlin is given by(a) M = Zp/

1.	The design capacity of channel/I-section purlin is given by(a) M = Zp/fy(b) M = Zpγm0fy(c) M = Zpγm0/fy(d) M = γm0/fyI have been asked this question in unit test.This question is from Purlins topic in chapter Design of Beams of Design of Steel Structures
Answer» The correct choice is (b) M = Zpγm0fy To explain: The design capacity of channel/I-section purlin is given by Mdz = Zpzγm0/fy and Mdy = Zpyγm0/fy , Mdz and Mdy are design moment capacity about Z and Y axes, respectively, Zpz and Zpyare plastic section modulus about Z and Y axes, respectively and fy is yield stress of STEEL. For SAFETY, design moment capacity should be ALWAYS GREATER than or equal to factored bending MOMENTS.

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The design capacity of channel/I-section purlin is given by(a) M = Zp/fy(b) M = Zpγm0fy(c) M = Zpγm0/fy(d) M = γm0/fyI have been asked this question in unit test.This question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

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