1.

The diagonal AC and BD of a parallelogram ABCD intersect at O.if OA=2x-3,OC=y+4,OB=x+3 and OD=2y-1, find the values of x and y.

Answer» X = 6 ; y = 5Step-by-step explanation:Diagonals of a parallelogram, bisect each other.Here, O is the point of intersection.So, OA = OC and OB = OD2x - 3 = y + 42x - y = 7...(i) andx + 3 = 2y - 1x - 2y = -4....(ii)Solving EQUATIONS (i) and (ii) using (i) - 2×(ii) we get,2X - y - 2x + 4y = 7 + 83y = 15Y = 5 andx - 2×5 = -4X = 6Hence, x = 6 and y = 5.


Discussion

No Comment Found