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the diagonal AC of a quadrilateral ABCD is 6cm and the perpendiculars, BM from the vertex B is 3 cm and DN from D is 5 cm , dropped on the same diagonal. find the area of rhe quadrilateral ABCD. |
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Answer» GIVEN :- the diagonal AC of a quadrilateral ABCD is 6cm and the PERPENDICULARS, BM from the vertex B is 3 cm and DN from D is 5 cm , dropped on the same diagonal. find the area of the quadrilateral ABCD. Solution :- we have, → Length of diagonal AC = 6 cm → Perpendicular distance BM = 3 cm → Perpendicular distance DN = 5 cm so, → Area of quadrilateral ABCD = (1/2)[ sum of Perpendicular distance on diagonal ] * Diagonal length putting values we get, → Area of quadrilateral ABCD = (1/2) * (3 + 5) * 6 → Area of quadrilateral ABCD = 8 * 3 → Area of quadrilateral ABCD = 24 cm² (Ans.) Learn more :- Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी. Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f RESPECTIVELY... |
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