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The diagram shows three cases. In all the three cases the circular part has radius r and straight ones are infinitely long . For the same current, i find barB at the centre P. |
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Answer» Solution :a) `barB_p = (mu_0i)/(4r)odot` B) `barB_2 = B_P = 1/2 (mu_0i)/(2r) ox = (mu_0i)/(4r) ox` C) `barB_p = (3)/(4)(mu_0i)/(2r) ox + (mu_0 i)/(4pi r) odot = (mu_0)/(4)(i)/(r) (3/2 - 1/pi) ox` |
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