1.

.the diameter of a 120 cm long roller is 84 cm It takes 1000 complete revolutions in moving once over to level a playground what is the area of the playground​ ​ ​o​

Answer»

\huge\bold\blue{Answer}

Diameter of roller = \tt {84 cm }

Radius = \tt { \frac{84}{2}}= \tt {42 cm}

LENGTH of roller = \tt {120 cm }

CSA of the roller = \tt {2πrh}

= \tt {2 \times  \frac{22}{7}   \times 42 \times 120}

= \tt {31680}

The AREA covered by the roller in 1000 revolutions = \tt {31680 × 1000}

= \tt {31680000 {cm}^{2}}

Hence,

The area of the PLAYGROUND =

\tt {\frac {31680000{cm}^{2}}{100×100}} = \tt {3168 {m}^{2}}

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