Saved Bookmarks
| 1. |
the diameter of a road roller is 18 cm and it is 2.8cm long. How much area will it cover in 25 revolutions in levelling a road |
|
Answer» -step explanation:so FIRST we have to find the lateral SURFACE AREA of road roller lateral surface area of road roller = 2πrh here diameter is given so we have to divide it with 2 to find radius SO= 18/2= 9 it's the radiusnow put the value = 2 × 22/7 × 9 × 2.8= 158.4 SQUARE cm now how much area covered in 25 revolution = 158.4 × 25= 3960 square cm |
|