The diameters of a circle are along 2x+y−7=0 and x+3y−11=0 Then th – InterviewSolution

1.	The diameters of a circle are along 2x+y−7=0 and x+3y−11=0 Then the equation of this circle, which also passes through (5,7) is
Answer» The diameters of a circle are along $2 x + y - 7 = 0$ and $x + 3 y - 11 = 0$ Then the equation of this circle, which also passes through (5,7) is

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