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The dielectric permittivity of gaseous argon at standard conditions is 1.00054. Find the dipole moment of an argon atom in an electric field of 10 kV/m. Compare with the dipole moment of a water molecule. |
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Answer» Solution :A characteristic feature of the INERT gases is their DEFORMATION polarizability. From the formulas of 38.5 we have `che_(e)=n alpha` where `n=p//kT` is the ATOMIC concentration and a is the polarizability of the atom. The dipole MOMENT of an atom in an electric field is `pe=alpha epsi_(0)E=(1)/(n) chi_(e)epsi_(0)E` The atomic concentration at standard conditions is Loschmidt number). Hence `pe=(chi_(e)epsi_(0)E)/(N_(L))=((epsi-1)epsi_(0)E)/(N_(L))` Calculations show that even in such strong fields the dipole moment of an argon atom is six orders of magnitude smaller than that of a water MOLECULE |
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