InterviewSolution
Saved Bookmarks
| 1. |
The dielectric strength of air is 3.0 x 106V/m. A parallel-plate air-capacitor has area 20cm2 and plate separation 0.10mm. Find the maximum rms voltage of an AC source which can be safely connected to this capacitor. |
|
Answer» E = 3 × 106V/m, A = 20cm2, d = 0.1mm Potential diff. across the capacitor = Ed = 3 × 106 × 0.1 × 10–3 = 300V Max. rms Voltage = V/√2 = 300/√2 = 212V |
|