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The difference between `DeltaH` and `DeltaE` (on a molar basis) for the combustion of n-octane `(l)` at `25^(@)C` would be:A. `-13.6KJ`B. `1.14KJ`C. `-11.15KJ`D. `+11.15KJ` |
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Answer» Correct Answer - D `C_(8)H_(18)(l)+(25)/(2)O_(2)(g)rarr8CO_(2)(g)+9H_(2)O(l)` `Deltan_(g)=8-(25)/(2)=(16-25)/(2)=-4.5` `DeltaH-DeltaE=Deltan_(g)RT=-(4.5xx8.314xx298)/(1000)=-11.15KJ` |
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