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The difference in the value of `g` at poles and at a sphere of latitude, `45^(@)` isA. `Romega^(2)`B. `(Romega^(2))/2`C. `(Romega^(2))/4`D. `(Romega^(2))/3` |
Answer» Correct Answer - B `g_(phi)=g-Romega^(2)cos^(2)phi, g_("poles")=g` |
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