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The differential equation `(dy)/(dx)+P y=Q y^n , n >2`can be reduced to linear form y substituting`z=y^(n-1)`b. `z=y^n`c. `z=y^(n+1)`d. `z=y^(1-n)`A. `z=y^(n-1)`B. `z=y^(n)`C. `z=y^(n+1)`D. `z=y^(1-n)`

Answer» Correct Answer - D
We have, `(1)/(y^(n))(dy)/(dx)+P(1)/(y^(n-1))=Q`
It reduces to linear form by substituting `(1)/(y^(n-1))=z`


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