The dimension of a rectangular box are in the ratio of 2:3:4 and the difference between the cost of covering it which sheet of paper at the gates of rupees 8 and rupees 9.50 per metre square is rupees 1248.Find the dimension of the box.PLZ ANSWER BRIEFLY.

The dimension of a rectangular box are in the ratio of 2:3:4 and the d

1.	The dimension of a rectangular box are in the ratio of 2:3:4 and the difference between the cost of covering it which sheet of paper at the gates of rupees 8 and rupees 9.50 per metre square is rupees 1248.Find the dimension of the box.PLZ ANSWER BRIEFLY.
Answer» Let DIMENSION of a rectangulqr box be 2x 3X and 4x then TSA = 2 ( 2x * 3x + 3x * 4x + 4x * 2x ) = 52 x^2 C1 = cost of coveribg at rs.8/unit = 52x^2 * 8 C2 = cost of covering at rs.9.50 = 52x^2 * 9.50 given C2 - C1 = 1248 52x^2 * 9.50 - 52x^2 * 8 = 1248 taking 52x^2 common 52x^2 ( 9.50 - 8) = 1248 52x^2 * 3/2 = 1248 78x^2 = 1248 x^2 = 1284 / 78 x^2 = 16 x = 4 then. dimensions are = 8m , 12m , 16 m hope it helps.. plz. MARK as brainly.....