1.

The dimensional formula for magnetic flux is :

Answer»

`[ML^(2)T^(-2)A^(-1)]`
`[ML^(0)T^(-2)A^(-2)]`
`[M^(0)L^(-2)T^(-2)A^(-2)]`
`[ML^(2)T^(-1)A^(3)]`

Solution :`phi=ABcostheta` where `A`=area, `B`=magnetic INDUCTION
`:.phi=[L^(2)xxML^(0)T^(-2)A^(-1)]`
`=[ML^(2)T^(-2)A^(-1)]`
`:.(a)`is CORRECT CHOICE.


Discussion

No Comment Found

Related InterviewSolutions