1.

The dimensional formula of B^2/(2mu_0) is……

Answer»

`M^-1 L^1 T^2`
`M^1 L^-1 T^-2`
`M^-1 L^-1 T^-2`
`M^1 L^1 T^2`

Solution :Here `B^2/(2mu_0)` is electromagnetic ENERGY DENSITY.
HENCE its DIMENSIONAL formula =`([energy])/([volume])`
`=(M^1L^2T^-2)/L^3=M^1L^-1T^-2`


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