InterviewSolution
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InterviewSolution
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The dimensions of permittivity `epsilon_(0)` areA. `ML^(3) T^(-4) A^(2)`B. `M^(-1) L^(-3) T^(4) A^(2)`C. `ML^(3) T^(-4) A^(2)`D. `ML^(-3) T^(-4) A^(2)` |
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Answer» Correct Answer - B (2) `F = (1)/(4 pi epsilon_(0)) (q_(1) q_(2))/(r^(1)) implies epsilon_(0) = (q_(1) q_(2))/(4 pi F r^(2))` Unit of `epsilon_(0) : ((c o u l)^(2))/(N m^(2)) = ([AT]^(2))/([MLT^(-2)] [L]^(2))` ltbgt `[epsilon_(0)] = M^(-1) L^(-3) T^(4) A^(2)` |
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