1.

The dimensions of 'resistance' are same as those of. . . . . . . . .Where h is the Planck's constant e is the charge .

Answer»

`(h)/(E^(2))`
`(h)/(e)`
`(h^(2))/(e^(2))`
`(h^(2))/(e)`

Solution :`R=(V)/(I)=(W)/(q.I)=(ML^(2)T^(-2))/(A^(2)T)=ML^(2)T^(-3)A^(-2)`
Dim. Of `(h)/(e^(2))=(ML^(2)T^(-1))/(A^(2)T^(2))=[ML^(2)T^(-3)A^(-2)]`
So CORRECT choice is `(a).


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