1.

The dimensions of universal gravitational constant are :-A. `ML^2 T^(-1)`B. `M^(-2)L^3 T^(-2)`C. `M^(-2) L^2 T^(-1)`D. `M^(-1) L^3 T^(-2)`

Answer» Correct Answer - D
`because F=(Gm_1m_2)/r^2`
`therefore [G] =[(Fr^2)/m^2]=(MLT^(-2)L^2)/M^2`
`=M^(-1)L^3T^(-2)`


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