The diode used in figure requires minimum current of 1 mA to be above the knee voltage 0.7 of current versus voltage characteristics. The maximum value of R so that the voltage is above knee pointis :

The diode used in figure requires minimum current of 1 mA to be above

1.	The diode used in figure requires minimum current of 1 mA to be above the knee voltage 0.7 of current versus voltage characteristics. The maximum value of R so that the voltage is above knee pointis :
Answer» `5 kOmega` `5.7 kOmega` `4.3 kOmega` `3.5 kOmega` SOLUTION :`i=(V_F-V_B)/R` `implies R=(V_F-V_B)/i=(5-0.7)/(10^(-3))=4.3xx10^3Omega` `=4.3 kOmega`

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The diode used in figure requires minimum current of 1 mA to be above the knee voltage 0.7 of current versus voltage characteristics. The maximum value of R so that the voltage is above knee pointis :

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