1.

The diode used in the circuitshown in the figure has a constant voltage drop at 0.5 V at all currents and a maximumpower rating of 100 milliwatts. What should be the value of the resistor R, connected in series with diode, for obtaining maximum current?

Answer»

6.76 `Omega`
20`Omega`
5`Omega`
5.6`Omega`

Solution :As `R_D=V_D^2/P_D =(0.5V)^2/(0.1 W)=2.5 Omega`
So, CURRENT , `I_D=V_D/R_D`=0.2 A
TOTAL resistance required in the circuit ,
`R_(eq)=V/I_D=1.5/0.2=7.5 Omega`
`therefore` Resistance of the SERIES resistor , `R=R_(eq)-R_D`
= 7.5-2.5 = 5 `Omega`


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