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The dipole moment of a dipole is 4 xx 10^(-9) Cm. The po1ential of a point away from 0.2 rn, the direction maJting an angle 60^(@) with axis of dipole is ......... |
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Answer» Solution :`V = (kq COS theta)/(r^(2))=(9XX10^(9)xx4xx10^(-9)xxcos 60^(@))/((0.2)^(2))` `= (3.6xx1)/(0.04xx2) = 450 V` |
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