InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The dipole moment of `HBr` is ` 1.6 xx 10^(-30) cm` and interatomic spacing is `1 Å`. The `%` ionic character of `HBr` isA. 7B. 10C. 15D. 27 |
|
Answer» Correct Answer - B Charge of electron=`1.6xx10^(-19)`C Dipole moment HBr=`1.6xx10^(-30)` cm Interiodic spacing =1 Ã… =`1xx10^(-10)` m Considering HBr to be ionic , dipole moment =`1.6xx10^(-19) C xx 10^(-10)m` `=1.6xx10^(-29)` Cm Therefore, percentage ionic character of HBr =`(1.6xx10^(-30))/(1.6xx10^(-29))xx100=10%` |
|