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The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________ % of the initial voltage.(a) 33(b) 63(c) 37(d) 36The question was posed to me during an online exam.I'm obligated to ask this question of Analysis of Growth & Decay topic in section Inductance in a DC Circuit of Basic Electrical Engineering

Answer»

Right choice is (c) 37

For EXPLANATION: We know that: V=V0(e^-tR/L).

When t=L/R, we have: V=V0(e^-1) = 0.37*Vsub>0.

Hence the time constant is the time TAKEN for the voltage in an inductive circuit to become 0.37 times its INITIAL voltage.



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